alphabet = "abcdefghijklmnopqrstuvwxyz"
alphabetList = []
for i in alphabet:
alphabetList.append(i)
print(alphabetList)
The intended outcome is to determine where the letter is in the alphabet using a while loop
- What is a good test case to check the current outcome? Why?
- Make changes to get the intended outcome.
letter = input("What letter would you like to check?")
i = 0
while i < 26:
if alphabetList[i] == letter:
print("The letter " + letter + " is the " + str(i+1) + " letter in the alphabet")
i += 1
The intended outcome is to determine where the letter is in the alphabet using a for loop
- What is a good test case to check the current outcome? Why?
- Make changes to get the intended outcome.
letter = input("What letter would you like to check?")
count = 1
for i in alphabetList:
if i == letter:
print("The letter " + letter + " is the " + str(count) + " letter in the alphabet")
count += 1
This code outputs the even numbers from 0 - 10 using a while loop.
- Analyze this code to determine what can be changed to get the outcome to be odd numbers. (Code block below)
evens = []
i = 0
while i <= 10:
evens.append(i)
i += 2
print(evens)
This code should output the odd numbers from 0 - 10 using a while loop.
odds = []
i = 1
while i <= 10:
odds.append(i)
i += 2
print(odds)
This code outputs the even numbers from 0 - 10 using a for loop.
- Analyze this code to determine what can be changed to get the outcome to be odd numbers. (Code block below)
numbers = [0,1,2,3,4,5,6,7,8,9,10]
evens = []
for i in numbers:
if (numbers[i] % 2 == 0): # % is modulus that returns remainder
evens.append(numbers[i])
print(evens)
This code should output the odd numbers from 0 - 10 using a for loop.
numbers = [0,1,2,3,4,5,6,7,8,9,10]
odds = []
for i in numbers:
if (numbers[i] % 2 == 1):
odds.append(numbers[i])
print(odds)
The intended outcome is printing a number between 1 and 100 once, if it is a multiple of 2 or 5
- What values are outputted incorrectly. Why?
- Make changes to get the intended outcome.
numbers = []
newNumbers = []
i = 0
while i <= 100:
numbers.append(i)
i += 1
for i in numbers:
if numbers[i] == 0:
pass # if it's zero, do nothing, you can also use continue, if it's equal to zero, skip to loop and bypass the code and do the same thing
elif numbers[i] % 5 == 0:
newNumbers.append(numbers[i])
elif numbers[i] % 2 == 0: # if it doesn't do first one, it does this, otherwise, nothing happens
newNumbers.append(numbers[i])
print(newNumbers)
Challenge
This code segment is at a very early stage of implementation.
- What are some ways to (user) error proof this code?
- The code should be able to calculate the cost of the meal of the user
Hint:
- write a “single” test describing an expectation of the program of the program
- test - input burger, expect output of burger price
- run the test, which should fail because the program lacks that feature
- write “just enough” code, the simplest possible, to make the test pass
Then repeat this process until you get program working like you want it to work.
my_Menu = {"pasta": 7.08,
"pizza": 11.53,
"breadstick": 0.99,
"drink": 1.09} # define my menu as a dictionary data type, key is the name of food, value is the price
price_total = 0 #set initial value, default value means function argument will take this value if no argument value is passed during function call
print("======================") #print menu decoration line on top
print("~~~ Kaylee's Menu ~~~")
# print a nice menu that allows user to choose from
for x,y in my_Menu.items():
print(x,": ","$",y)
print("======================") #print menu decoration line at bottom
print("Welcome to Kaylee's Italian Food Truck, what would you like to order from our menu?")
myUserInput = "pasta" #define and set initial value
myUserInput = input() #define variable to hold user input
myUserOrderKey = myUserInput #define and set initial value-- used to print out user's selected key and value
myCounter = 0 #count through the loop
myTotalOrderQuestion = "How many " + myUserInput + "s would you like to order?"
myError = "Sorry, we don't have '" + myUserInput + "' in our menu"
totalUserInput = 0 #define variable
for x,y in my_Menu.items(): #loop through my menu
if x == myUserInput: #if the user input matches a key in my menu4
print("Your order is: ",x,y) #then print the key and value
break #stop looping when you get result
else:
myCounter += 1
if myCounter == 4: # if loop four times, it means we don't have the item in the menu
print(myError)
if myCounter != 4:
print(myTotalOrderQuestion)
totalUserInput = int(input()) #only get user input when you need it, otherwise it will always prompt
myUserTotal = "Your total for " + str(totalUserInput) + " "+ x +"(s) is $" + str(y*totalUserInput)+ ". Enjoy!"
if totalUserInput >= 1:
print(myUserTotal)
else:
print("Please give a number of at least one.")
Hacks
Now is a good time to think about Testing of your teams final project...
- What errors may arise in your project?
- What are some test cases that can be used?
- Make sure to document any bugs you encounter and how you solved the problem.
- What are “single” tests that you will perform on your project? Or, your part of the project?
- As Hack Design and Test plan action … Divide these “single” tests into Issues for Scrum Board prior to coding. FYI, related tests could be in same Issue by using markdown checkboxes to separate tests.